Questions tagged [self-energy]

Quantum-mechanical object that captures some of the characteristics of particles associated to interactions with themselves and with other particles, such as the change in its mass as a function of its energy. Particularly useful in quantum field theory, either for relativistic particle physics or condensed matter physics. Although it also makes sense as a classical concept, it mostly has fallen into disuse nowadays.

Background.

In general terms, the self-energy $\Pi_{ij}(x)$ of a field $\phi^i(x)$ is defined as the inverse of its two-point function: $$ \int_{\mathbb R^d}\Pi_{ij}(x-y)G^{jk}(y-z)\ \mathrm dy\equiv\delta(x-z)\delta_i^k $$ with $G^{jk}(y-z)\equiv \langle \phi^i(y)\phi^j(z)\rangle$.

In perturbation theory, $\Pi(x)$ can be calculated by summing all one-particle-irreducible Feynman diagrams with two external legs. For this reason, $\Pi(x)$ plays an essential role in the study of the renormalisability of the theory.

Among other things, this function carries the information about the masses of the particles described by $\phi$. In particular, the Fourier transform $\tilde\Pi(p)$ vanishes at $p^2=\mu^2$ if and only if $\phi(x)$ creates a particle of mass $\mu$. This means that, for example, the system is gapless if $\tilde\Pi(p)=cp^2+\mathcal O(p^4)$ for some constant $c$.

For more details see the Wikipedia page self-energy.

186 questions
25
votes
3 answers

Self-energy, 1PI, and tadpoles

I'm having a hard time reconciling the following discrepancy: Recall that in passing to the effective action via a Legendre transformation, we interpret the effective action $\Gamma[\phi_c]$ to be the generating functional of 1-particle irreducible…
13
votes
2 answers

How to correctly understand these "1-particle-irreducible insertions"?

In QED, when dealing with the vacuum polarization and the photon propagator, some authors like Peskin & Schroeder introduce the so-called "1-particle irreducible" diagrams. These are defined as: Let us define a one-particle irreducible (1PI)…
13
votes
1 answer

On the asymptotics of interacting correlation functions

Consider an interacting QFT (for example, in the context of the Wightman axioms). Let $G_2(x)$ be the two-point function of some field $\phi(x)$: $$ G_2(x)=\langle \phi(x)\phi(0)\rangle $$ Question: What is known about the behaviour of $G_2^{-1}(p)$…
12
votes
1 answer

Where are the poles of the one-particle Green's function located in the complex plane?

This post is a followup question to: How to get an imaginary self energy? In the cited post, the two following representations for the one-particle Green's function are shown: $$G(k,\omega) = \sum_n \frac{|c_k|^2}{\omega - E_n +…
11
votes
3 answers

Why is the electron self-energy gauge dependent?

Let $\psi(x)$ be the field of the electron. Its Fourier transformed two-point function reads $$ \langle\psi\bar\psi\rangle=\frac{1}{\not p-m-\Sigma(\not p)}. $$ If we calculate $\Sigma(\not p)$, we observe that it depends on the gauge parameter…
11
votes
2 answers

What's the relation or difference between Lippmann-Schwinger equation and Dyson equation?

In quantum scattering theory, Green's Function is defined as [1] $$G_0(z)=(z-H_0)^{-1},$$ $$G(z)=(z-H)^{-1},$$ where $H_0$ and $H=H_0+V$ are separately non-interacting and interacting Hamiltonian. $V$ is interaction. One can then use the…
10
votes
1 answer

Random walk recurrence term and the self-energy

Consider the "first passage problem" A random walk proceeds on a graph of connected points. On this graph, there is one "end" point $j$ meaning that if the random walker lands on this point the process ends. Suppose we wish to know the mean…
DanielSank
  • 25,766
9
votes
1 answer

Is self-energy $\mathrm{Im}\Sigma^r<0$ always true?

Consider a one-particle retarded Green's function $$G^r(\alpha)=[\omega+i\eta-\varepsilon(\alpha)-\Sigma^r(\alpha)]^{-1}$$ with self-energy $\Sigma^r(\alpha)$ for some quantum number $\alpha$. It is argued that $-\mathrm{Im}\Sigma^r>0$ always holds…
9
votes
1 answer

Is Ward identity really satisfied by the photon's self-energy?

The one-loop self-energy of the photon, , when contracted with the external momentum $k^\mu$ gives the following difference of integrals where the integration variable in the first term is shifted compared to the second term. $$ k_\mu\Pi^{\mu\nu}(k)…
9
votes
1 answer

Self-energy of an electron

In his 1947 paper, Bethe states that the self-energy of an electron in a quantum state $m$, due to its interaction with transverse electromagnetic waves is $$W = -\frac{2e^2}{3\pi\hbar…
9
votes
1 answer

How can we use geometric series in calculating Green's function sum over loop effects

I found Greens function summing over repeated insertion of 1PI in Schwartz p.330: $$ \begin{aligned} iG(\not p)&=\frac{i}{\not p-m}(i\Sigma(\not p))\frac{i}{\not p-m}+\frac{i}{\not p-m}(i\Sigma(\not p))\frac{i}{\not p-m}(i\Sigma(\not…
8
votes
1 answer

Equation $7.22$ in Peskin & Schroeder: writing the Fourier transform of a two-point function as a series of 1PI diagrams

In Peskin and Schroeder's QFT book, on page $219$, there is the following equation: The heading to the equation is: "The Fourier transform of the two-point function can now be written as". Could someone help me formally prove this formula? I don't…
8
votes
0 answers

Self-energy that does not obey sum rule

Analytically, I calculated a self-energy $\Sigma(\omega)$, for which I verified that 1) $\text{Im}\big[\Sigma(\omega)\big] \leq 0$ for all $\omega$ and specifically $\text{Im}\big[\Sigma(0)\big] = 0$, 2) $\text{Im}\big[\Sigma(\omega)\big] = 0$ for…
8
votes
1 answer

Ward Identity makes QED logarithmic divergent?

Quick question regarding superficial degrees of freedom and Ward identities. For instance in Peskin and Schroeder it is stated that the photon-self energy is superficially quadratically UV divergent but due to the Ward identity it is only…
8
votes
2 answers

Divergent self-energy of point charges in Classical Electrodynamics

Assuming the electron to be a classical point particle, if one calculates the self-energy one finds $$U=\frac{e^2}{8\pi\epsilon_0r}$$ which diverges as $r\rightarrow 0$. Therefore, the measured mass of the electron should be…
1
2 3
12 13