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Operators in Heisenberg picture are time-dependent while those in Schrödinger picture are time-independent, and they are related by $$A_H(t)=U^\dagger(t,t_0)A_S(t_0)U(t,t_0)$$ where $U(t,t_0)$ is the unitary evolution operator.

Does it mean it is not possible to work with the Schrödinger picture for time-dependent Hamiltonians? If yes, what does it even mean, in this case, to work in the Schrodinger picture because the operators are time-dependent?

Qmechanic
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SRS
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1 Answers1

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Yes, it's perfectly possible. You just pose the Schrödinger equation, $$ i\hbar\partial_t |\psi(t)\rangle = \hat H(t)|\psi(t)\rangle, $$ and you solve it. Or what do you mean by "how does that work?"?

Emilio Pisanty
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