To answer this question you just need to know that the force scale like the transection surface of a muscle. In other words the bigger the muscles the stronger. Therefore you have
$F ∝ σ_s S$,
where $σ_s$ is the maximum developed muscle stress. It so happens that on earth the muscles work pretty much the same in all the animals (from the ants all the way up to the elephant) so it is pretty universal (it can still vary from one species to another but not by one order of magnitude). For mammals it is around 10 N/cm$^2$.
Then the general allometric law (or spherical cow argument) gives :
$l∝ M^{1/3}$,
$S ∝ l^2 ∝ M^{2/3}$,
where M is the animal weight.
Ok now let's consider the problem of lifting up a weight of mass $M_0$. To do so you have to lift up your own weight plus this mass using your muscles :
$F \sim (M+M_0)g $
$\dfrac{σ_s}{ρ^{2/3}}M^{2/3} \sim (M+M_0)g$
$\dfrac{M_0}{M} \sim a M^{-1/3} -1$
You thus see that the mass that an animal can lift up compare to its weight scale like $M^{-1/3}$. This leads to the impressive strength of ants.
Interestingly enough, you can also use this in a single species to compare the stronger and the heaviest :
$M_0 \sim a_h M^{2/3}(1-\dfrac{M{1/3}}{a_h})$
This function as a maximum ($\dfrac{dM_0}{dM}(M_{strongest}) = 0$) and 2 values for which M_0 = 0 (M=0, boring ; and $M_{heaviest} = a_h^3$. You will easily check that :
$M_{strongest} =\dfrac{8}{27}M_{heaviest}$.
Ok so what? well if you use it for human, we can estimate the value of $a_h$ using the weight of the heaviest man ($M_{heaviest} = 635 kg, Jon Brower Minnoch). Therefore the strongest man should be around 190kg. Well this is exactly the weight of the "strongest man" the Iranian Hossein Reza Zadeh...
Best,
Rémi