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Can we find momentum in finite square well potential? If so how can we find it? Does the eigenfunction of momentum operator is same as eigenfunction of Hamiltonian operator?

Qmechanic
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professor T
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1 Answers1

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If the potential well is finite, then the Hilbert space is the same as for the free particle: $L^2(R)$. The momentum operator is the usual one. Its improper eigenvectors are not eigenvectors of the Hamiltonian.

Valter Moretti
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