0

I'm struggling to find a hermitian operator whose eigenstate is a gaussian function in $|\psi(x)|^2$. How do i do this?

Just to be clear, this is in order to realistically model the wavefunction collapse when 'position' is measured, so the eigenvalue must be the mean of the gaussian

1 Answers1

3

The ground state wavefunction of the Harmonic oscillator is given by a gaussian function $$\psi_0(x)=Ce^{-m\omega x^2/2\hbar}$$ The Hamiltonian of the harmonic oscillator looks like $$\mathcal{H}=\frac{P^2}{2m}+\frac{1}{2}m\omega X^2$$ Or on a position basis $$\mathcal{H}=-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}+\frac{1}{2}m\omega x^2$$

Himanshu
  • 12,211