You can think of an MPS as being built up by objects with three indices. How to easily represent such an object? We can think of this as a matrix where each entry is a vector (in particular the vector will be a vector in the on-site Hilbert space, so e.g. for a spin 1/2 system it will be of the form $\alpha |\uparrow \rangle + \beta |\downarrow \rangle$).
So for a chain where the on-site Hilbert space is a spin 1/2, each site will have such an object associated to it, like this:
$$ A = \left( \begin{array}{ccc} \alpha_{11} \;| \uparrow \rangle + \beta_{11} \; |\downarrow \rangle & \alpha_{12} \;| \uparrow \rangle + \beta_{12} \; |\downarrow \rangle & \cdots \\
\alpha_{21} \;| \uparrow \rangle + \beta_{21} \; |\downarrow \rangle & \alpha_{22} \;| \uparrow \rangle + \beta_{22} \; |\downarrow \rangle & \cdots \\
\vdots & \vdots & \ddots \end{array} \right)$$
If it is a translationally invariant system, we can have that every site has the same $A$ associated to it. The physical state of our system is then obtained by multiplying all these $A$ matrices (where we `multiply' the matrix elements via the tensor product structure), more precisely:
$$|\psi \rangle = \textrm{Tr}(A^N)$$
where we have assumed periodic boundary conditions. Here $N$ is the number of sites. Note that this object is now purely a vector in the tensor product of the on-site Hilbert spaces. So for example in the simple case that
$$ A = \left( \begin{array}{cc} |\uparrow \rangle & 0 \\
0 & |\downarrow \rangle \end{array} \right)$$
then
$$ A^N = \left( \begin{array}{cc} |\uparrow \rangle \otimes |\uparrow \rangle \otimes \cdots \otimes |\uparrow \rangle & 0 \\
0 & |\downarrow \rangle \otimes |\downarrow \rangle \otimes \cdots \otimes |\downarrow \rangle\end{array} \right)$$
So with periodic boundary conditions we get the cat state $|\psi \rangle = |\uparrow \cdots \uparrow \rangle + |\downarrow \cdots \downarrow\rangle$.
That answers your (ii). I'll leave (i) as an exercise ;)
