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If a photon has lower Energy (b.e.) it must pass a high energy filter unaltered. Let it be a red photon through a blue filter. As a photon is in fact a package of many waves with different wavelengths (if it has Poisson distribution there would be also blue wavelengths) and its energy cannot be divided - How does it pass a filter unaltered? The filter can cut its higher frequencies but they posses energy. So 'part' of the photon would be cut off by the filter and it would be very much different both in shape and energy.

Mercury
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In the mainstream theory of physics, a photon is an elementary point particle , of energy $hν$ where $h$ is Planck's constant $ν$ is the that frequency a large number of photons of that energy,will have as classical electromagnetic radiation. A photon is not a bundle of classical electromagnetic waves, classical waves develop from the underlying quantum field theory of particles.

So depending on the type of filter a photon will either go through unscathed or interact with the fields if the filter changing its energy accordingly.

anna v
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