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According to Is there a simple way of finding the eigenstates of the creation and annihilation operator in QM?

The creation operator has no eigenstates. But one postulate of QM says that the state of a system after measuement using an operator must be an eigenstate of that operator. How to make sense of this?

Qmechanic
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1 Answers1

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Not all operators are observables. Only self-adjoint operators are observables. A property of self-adjoint operators is that they have real eigenvalues.

The creation operator is not an observable and is not a self-adjoint operator. It's okay for an operator not to have eigenstates and not to be an observable.

Only observables can be measured.

Alwin
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