Consider a lab frame and the frame of an object rotating within it. Set up up a light clock of two mirrors and a beam of light that rises and falls vertically having a height z0. While in the lab frame, the light beam goes up and down vertically, in the rotating frame, the beam travels along the surface of a cylinder, traversing a longer distance also at the speed of light. The surface of a cylinder has no intrinsic curvature and vertical motion is perpendicular to the direction of motion. Does this imply time dilation $t=\frac{t_0}{\sqrt{1-\frac{(\omega r)^2}{c^2}}}$?
Here $t$ is time to the observer at the center of the rotational frame , $t_0$ is time in the lab frame, $\omega$ is the rotational velocity, and $r$ is the radial distance between the axis of the rotating frame and the light lock.
I'm thinking something is off because this seems to imply $\omega r$ must be less than $c$, but that corresponding product for the rotation of the earth and the distance to Alpha Centauri is higher than that. It also seems to imply things go slower the further they are away from the axis.
I'm not sure where my reasoning fails though.
