How is 1 g on a planet different from 1 g in a space ship when we look at aging?

Question

This question has been asked before in the form of the 'Twin paradox' , and there are 42 pages of questions on this site alone when I search for 'twin paradox'.

For example

Does the twin paradox require both twins to be far away from any gravity field?

Clarification regarding Special Relativity

The counterargument has been 'that the traveling twin has to accelerate and therefore is not in an inertial frame of reference.'

OK, I believe that; it is consistent with the lay explanation of general relativity. This effect of gravitational time dilation was dramatically portrayed in the film 'Interstellar' when the crew goes to a planet near a black hole and everyone else gets a lot older.

So what happens if we use the 'equivalence principle' and provide a gravitational acceleration to the non traveling twin? I have read many scenarios described on this site where the observer will not be able to tell if he is on earth or on the accelerating spaceship, yet the many of the questions here on physics stack exchange are answered with the statement 'the spaceship traveler will age more slowly'.

If I can slow aging by 'dialing up gravity', or I can slow aging by traveling fast, why is there always the statement that 'the spaceship traveler will age more slowly'? Why does 1 g on a spaceship age you more slowly than 1 g on earth?

Answer 1

Why does 1 g on a spaceship age you more slowly than 1 g on earth?

The gravitational time dilation at Earth's surface is rather small, approximately 2.19 seconds per century, as I mentioned in this answer. But that time dilation is caused by the Earth's gravitational potential (which also determines the escape velocity), not its gravitational field strength (which determines the gravitational acceleration).

Such time dilation is negligible in the usual Twin Paradox scenarios. It's only significant in extreme gravity wells, eg near a white dwarf, neutron star, or black hole.

Acceleration itself does not cause time dilation, only the velocity which arises due to that acceleration causes time dilation. This is known as the clock postulate. For further details, please see How does the clock postulate apply in non-inertial frames?

The traveling twin in the Twin Paradox ages less than than the earthbound twin because the traveling twin has to switch inertial frames in order to return home. It's that change of reference frame that makes the big difference, not the acceleration. The acceleration is merely the mechanism whereby the change of reference frame is performed.

Answer 2

Suppose that the traveller twin in $t = -t_0$ is passing by the Earth with $v = 0.9 c$, and turns its engines on, in order to meet once again his brother at Earth. And to achieve this, the ship keeps the same acceleration $g$ until the moment of return.

At the moment $t_0$:

$$\frac{dt}{d\tau} = \frac{1}{{(1-0.9^2)}^{1/2}} = 2.294$$

For a frame at uniform acceleration $g$:

$$t = \frac{c}{g}senh\left(\frac{g\tau}{c}\right)$$ $$\frac{dt}{d\tau} = cosh\left(\frac{g\tau}{c}\right)$$

When $\tau = (+/-)45067942,31s$ => $t = (+/-)63206372,8s$ and $\frac{dt}{d\tau} = 2.294$

So, the total time until the twins meet again is: $t' = 2*45067942,31s = 2.86$ years for the traveller twin and $t = 2*63206372,8s = 4$ years for the Earth twin.

While both are under the same acceleration $g$, the gravitational potentials are very different.

In the Earth, it is enough to send a test mass faster than 11.4km/s for it escapes our well and never more return.

In an uniformly accelerated frame, there is no escape. If at any moment during the trip, a test mass is send to the Earth direction, with any velocity, one day the ship will meet it again, if the acceleration $g$ is never turned off.

It is almost a one directional black hole, in the meaning that there is no escape from any mass in the direction of the acceleration.

Answer 3

One G ages you the same way whether you are sitting on a beach on earth with a mai tai in your hand or in deep space, accelerating your rocket ship at 9.8 meters per second squared. Increasing your G force by moving to a more massive planet or by jazzing up your rocket engines will slow down your clocks in the same way.

Should you choose to perform experiments to verify this I would advise substituting the mai tai with Herradura Gold tequila mixed with fresh-squeezed pink grapefruit juice. Remember to repeat the experiment enough times to achieve statistical significance.

One more point: If you are looking for experimental proof that biological activity is slowed down in a speeding reference frame, note this: If you are sitting in that speeding frame looking at brownian motion through a microscope, your own internal processes will be slowed down in exactly the same manner as the brownian motion, and you will observe no slowdown of the brownian motion because YOU are slowing down too.