Understanding the relationship between the drag, which is the force of friction in the context of fluids, and the speed of relative motion is simpler than understanding the relationship in the context of friction between the surfaces of everyday solid objects. The law of static friction referred to in the question is at best a semi-empirical law. Let us try to understand this statement by repeating a thought experiment in combination with empirical knowledge about this phenomenon, which is elegantly described in the lecture on the webpage linked in this answer.
If we take a block with known weight $W$ and place if on an incline, we can change the angle of inclination $\theta$ fairly easily. At a particular inclination, we observe that the block slides down the incline with an approximately uniform speed. Using the Newton's first and second laws describing forces and our knowledge of trigonometry, we can then define the coefficient of friction as $\mu := \frac{W \sin{\theta}}{W \cos{\theta}} = \tan{\theta}$.
Clearly, executing a real-world experiment which behaves in this ideal fashion is exceedingly difficult, but we can observe this behavior in some time intervals of the block's motion over the incline. However, even if we are able to execute such delicate experimentation, it does not completely describe the underlying phenomenon. For instance, consider a metal block made of a single element (as pure as possible) placed on an incline constructed identically in a vacuum, with both contacting surfaces having identical roughness. In this case, we may observe that the block and incline fuse together. In effect, our ansatz for the law can describe semi-empirically, the behavior of a variety of surfaces with impurities and varying roughness which are in direct contact, but is incapable of precise predictions for general surfaces. Similarly, verifying that the coefficient of friction is independent of the relative speed between the surfaces, is a challenging task which requires delicate experimentation and is not a completely answered question at present.