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So I've been doing a lot of research on spinning black holes and fumbled upon the concept of a "naked singularity" where a gravitational singularity exists without an event horizon. Ignoring the physics-breaking problems and questions it raises, how would this behave in comparison to a spinning black hole?

For example(s): Would it have an accretion disk? Would matter still get spaghettify if it got too close? Could you get in and out to observe it while once you pass the even horizon of a reg black hole, you can't get out?

tl;dr, would it act the same as a regular spinning black hole?

Qmechanic
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buiud
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1 Answers1

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Assuming you are asking about the type of naked singularity you get if consider the Kerr solution with spin greater than 1.

In some respects this solution behaves just like a Kerr black hole. For example, there still is an innermost stable circular orbit. Hence it could still have an accretion disk with an inner edge. Tidal effects would also still diverge as you approach the singularity leading to "spaghettification".

However, there also some crucial differences: For example there is no photon sphere, meaning the object would look very different when view by the event horizon telescope. Also, most matter falling toward the singularity will miss the singularity and be flung back out.

(And of course, there is the singularity itself, for which we have no clue how it would interact with other objects or fields.)

TimRias
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