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In photoelectric effect, the intensity of light is directly related to the number of photons incident on metal. This is indicated by the photocurrent vs. voltage applied for different frequencies having the same saturation current.

Intensity= (No. of photons per unit time) x (Energy of one photon =hv)

So if frequency is increased keeping intensity constant, shouldn't the no of photons incident per unit time decrease and thereby saturation current should decrease?

ApparentIce
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1 Answers1

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for a given photosensitive material and frequency of incident radiation,saturation current is found to be proportional to the intensity of incident radiation whereas the stopping potential is independent of its intensity.

madhu
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