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Depending on the dimension and the symmetry and form of the potential, the energy eigenvalues of a quantum mechanical system have different functional forms. Eg. The particle in the 1D-box gives rise to $E_n \propto n^2$, the hydrogen atom $E_n \propto -\frac{1}{n^2}$ the harmonic oscillator $E_n \propto n + \frac{1}{2}$, and so on. My question now is, could there possibly exist a system with energy eigenvalues $E_{n,m}\propto f(n m)$, for example like $\propto -\frac{1}{nm}$ with $n,m\in \mathbb{N}$?

I suspect the way the Hamilton function is translated to QM operators might prohibit such a product formation, since a product of say momenta ($\vec{p}$) is translated into a successive action of momentum operators rather than the product of the action of two operators. Which in turn will result in a summation of terms depending on different quantum numbers.

The question arises from thinking about how prime numbers could occur in physics. Since say, there would be a system with $E_{n,m} = \hbar(n+1)(m+1)$ with $n,m\in\mathbb{N}^+$ it would mean exactly non-prime number multiples of $\hbar$ would be allowed energy levels. And the prime numbers would appear as gaps in its eigenvalue spectrum.

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Let $H_1$ be the Hamiltonian of a Harmonic oscillator, and let $m=\hbar=\omega=1$, that is, $$ H_1=\frac{1}{2}P_1^2+\frac{1}{2}X_1^2-\frac{1}{2} $$

Let $|n_1\rangle$ be the eigenvectors of $H_1$, i.e., $$ H_1|n_1\rangle=n_1|n_1\rangle $$

If we define $H=H_1 H_2$ with$^1$ $[H_1,H_2]=0$ we get multiplicative eigenvalues: $$ H|n_1,n_2\rangle=n_1n_2|n_1,n_2\rangle $$


$^1$ this is equivalent to $[X_1,X_2]=[P_1,P_2]=0$ and $[X_i,P_j]=i\delta_{ij}$, that is, the usual commutation relations.