Do the position-momentum uncertainty and time-energy uncertainty really exist in QFT?

Question

It is well known from the Quantum Mechanics(QM) that for a particle, there is a position-momentum uncertainty relation: $$\Delta x\cdot \Delta p\geq \frac{1}{2}\hbar,$$ which basically can be derived from the commutative relation of $\hat x$ and $\hat p$ $$[\hat x,\hat p]=i\hbar.$$ There is also a time-energy uncertainty relation which is a bit subtle. But it can be well understood by imagining T as an operator, where we must introduce a parameter of the particle's worldline.

Now comes the always very confused concept of position-momentum or time-energy uncertainty relations in QFT, especially in vacuum. In QFT we only have the commutative relations: $$[\hat\phi(\vec x,t),\hat\pi(\vec x',t)]=i\hbar\delta(\vec x-\vec x').$$ Following the standard process we only can obtain the uncertainty relation about $\hat\phi(\vec x,t)$ and $\hat\pi(\vec x,t)$. There is no space-momentum uncertainty or time-energy uncertainty at all since now spacetime are simply parameters! The time and space even have no explicit physical meanings as observables in QFT, especially in vacuum. Indeed the vacuum is a stationary state just like the ground state of the harmonic oscillator in QM, which has no energy fluctuations at all.

People always take it for granted that the position-momentum or time-energy uncertainty still exists in QFT. See my another question. People always like to say things like there is a minimal length because at smaller and smaller scale there is a bigger and bigger uncertainty of energy which will eventually creates a black hole. Note in such statement, people always mean the vacuum, namely there is no particle at all. These relations are also used by many other authors without any doubt, e.g. see also A.D. Linde where he wrote:

Note, that the value of $V(\phi)$ at $t\sim t_p\sim M^{-1}_p$ can be measured with an accuracy $\sim M^{4}_p$ only due to the uncertainty principle.

Does anybody know of a derivation of the time-energy uncertainty relation (or position-momentum relation) in relativistic QFT?

Answer 1

You are correct that approached formally QFT does not have position and time observables, they are background parameters like time in QM, which seems to go against the use of localized particles. As Baker writes:"Rigorous forms of the interacting theory cannot sustain a “quanta” interpretation in which the fundamental entities are countable. And even the free theory is provably unable to describe particles localized at or around points... it so happens that in non-relativistic QM, one of the observables ($\widehat{Q}$) meets the intuitive description of a particle position operator. So for any (one-particle) state $ψ$, the inner product $(ψ,\widehat{Q}ψ)$ can be interpreted as the expected value of the particle’s position. The way is open for a particle interpretation of QM. As Malament [1996] has shown, no such position operator exists in QFT. This may be the most convincing sign that a particle interpretation of the theory cannot succeed".

However, time is not an observable already in QM, and the time-energy uncertainty is not a canonical uncertainty relation there, something similar may hold for the position-momentum uncertainty in QFT. Moreover, rigorous forms of QFT are only known for toy models, and realistic QFT is perturbative only. Without knowing what the non-perturbative theory is we can not know for sure what interpretation it will or will not support.

The perturbative theory uses Feynman diagrams in calculations, and can be heuristically interpreted in terms of particles. Whatever the ultimate theory turns out to be it will have to reproduce this phenomenology at least effectively in some limit. Wallace gives an interesting account of interpretational issues in perturbative QFT, including the particle paradox:"The phenomenology of particle physics... makes extensive use of the concept of localisation: that is, of the concept that physical systems have at least some states which localised in finite spatial regions. There are a number of results in AQFT which apparently rule out the possibility of such states, and this is sometimes described as a paradox in QFT... it will be argued that nothing paradoxical is going on... Localisation enters this framework as a pragmatic criterion for isolation". So the position-momentum uncertainty relation may hold as a pragmatic heuristic in QFT even if it lacks fundamental status.