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As a beginner in QM, all the video lectures that i have seen talk about superposing wave functions in order to get $\psi$. But from what i know from linear algebra, the system must be linear in order for us to do this superposition.

So, what tells us that quantum systems are linear systems? Does it come out of experimental results or from some intuitive physical explanation? If it's the first, then if we treat all quantum mechanical systems as linear, how can we find a non-linear system that might exist but has not been seen in labs yet? (I mean that in this way we exclude all possibilities that a non linear quantum system might exist). If it's the second, then can you give me that intuitive explanation?

jck
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2 Answers2

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There is not a direct link between the linearity of some physical laws and the superposition of quantum mechanics. The latter is more of a special kind of linear superposition which requires some restrictions on the coefficients.

The existence of the phenomenon of superposition of states is a characteristic of quantum mechanics. In classical mechanics such a phenomenon does not exist because every irreducible representation of the corresponding algebra of observables is one dimensional. In order to have a superposition of states, higher dimensional irreducible representations are necessary, where the state space can then be identified with the projective representation vector (Hilbert) space. When at least two independent unit vectors, say $u,v$, are then available, one can construct any superposition $$w = \alpha u + \beta v,\qquad\alpha,\beta\in\mathbb C,$$ with the condition that $|\alpha|^2+|\beta|^2 = 1$. This is necessary to ensure that $w$ defines a state, i.e. a normalised linear functional on the algebra of observables. When you look at the operation of superimposing the states generated by $u$ and $v$ into the state generated by their superposition $w$ you see that this map is not linear, for once because the projective Hilbert space (which is in a one-to-one correspondence with the accessible states) is not a linear space (think of this as a map that takes two points on a sphere and spits out another point on the sphere; this analogy is not entirely perfect in this case but close enough, modulo some identifications of points).

When there is a equation that governs the dynamics in this framework, then the superposition principle applies if this equation is linear. The meaning of superposition is a bit different in this context. While you can still superimpose states in the sense above, if $u$ and $v$ are solutions of a non-linear equation, then $w$ need not be a solution of the same non-linear equation; nonetheless it is still a valid superimposition of the states $u$ and $v$.

Phoenix87
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I agree with Phoenix87 that the answer must contain a little bit of maths. Basic (nonrelativistic) quantum systems are well described by the Schrödinger equation, $H \psi = E \psi$, which is a linear (partial differential) equation: It contains the wave function $\psi$ only to the first power (no $\psi^2$ etc.). Thus, if two wave functions, say $\psi_1$ and $\psi_2$, obey the equation so will their sum or a general superposition, $\alpha \psi_1 + \beta \psi_2$ with complex $\alpha$ and $\beta$. This would not be true for a nonlinear equation.

Somewhat annoyingly (as far as terminology is concerned), there is a thing called the nonlinear Schrödinger equation, which describes classical solitons and has nothing (much) to do with quantum mechanics. From time to time, people have speculated about violations of linearity and the superposition principle, but tests have so far confirmed linearity (for a recent discussion, see e.g. this Nature Physics article).

Tom Heinzl
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