Level shift 4 V peak to peak to 0 - 3.3 V

Question

I need to convert a 4 V peak to peak signal (-2 V to +2 V) into a 0 to 3.3 V signal to get it into my ADC on LPC 11u24. I have tried several designs but the problem is that all of the designs I found are based on single rail op amps. I only have dual supply op amps. Any suggestions?

When you say 2v p-p do you mean bipolar like -1v to +1v (swinging above and below ground level) or just 0-2v ? — alexan_e, Jan 30 '14 at 17:00
You could try shifting the signal by adding DC using a summing amplifier with unity gain. — Pyxzure, Jan 30 '14 at 17:11
I only have dual supply op amps Why is that a problem preventing you from using the solutions you found for single rail opamps? — alexan_e, Jan 30 '14 at 18:26
You would add a DC voltage of 2V to the input signal so that its peak value is 0 to 4V. A diode voltage shifter which clamps the minimum to 0V is also possible. You convert this to 0V to 3.3V using a voltage divider or a b- directional level translator There seems no loss of resolution of signal in this way. — Amit M, Oct 05 '22 at 15:01
Speed of the signal might matter in your design. For low speed, the above may work. For high speed a CMOS solution might be better. — Amit M, Oct 05 '22 at 15:11

score 2 · Accepted Answer · edited Apr 13 '17 at 12:32

2

Based on this post, a summing amplifier could work. Adjusting the values, the schematic would be as follows:

schematic

^{simulate this circuit – Schematic created using CircuitLab}

The output is calculated just like a non-inverting amplifier. Thus, when the sine wave is +2V, the terminals of the op-amp are at 2V. Since

\$V_O = V_I(1+\frac{R_4}{R_3})\$

the output will be 3.3V. When the sine wave is -2V, the terminals will be 0V, since the two voltage sources, \$R_1\$, and \$R_2\$ act as a voltage divider. Then the output will also be 0V.

The caveat here is that you need a rail to rail op-amp, or supply voltages that are less than 0V and greater than 3.3V. Otherwise the op-amp will clip the output.

edited Apr 13 '17 at 12:32

Community

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answered Jan 30 '14 at 19:14

Justin Trzeciak

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There are also simpler, passive solutions here: http://electronics.stackexchange.com/questions/32318/how-can-i-measure-voltage-in-range-15v-to-50v-with-adc-in-microcontroller-in-a/32328#32328, http://electronics.stackexchange.com/questions/7583/how-do-i-sample-a-2-v-to-2-v-analog-signal-with-a-pic-microcontroller – Justin Trzeciak Jan 31 '14 at 13:06

score 0 · Answer 2 · answered Jan 30 '14 at 17:14

0

This will level shift your +/-1V signal, however it requires a low impedance source and you lose a couple (1.7) bits of resolution.

schematic

^{simulate this circuit – Schematic created using CircuitLab}

answered Jan 30 '14 at 17:14

Spehro Pefhany

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Can you explain the resolution loss? – dext0rb Jan 30 '14 at 17:26
The network above gives you a -3.3 to 3.3V range (6.6V p-p) as your signal is only 2V p-p, you lose $log_2$(3.3) bits. – Spehro Pefhany Jan 30 '14 at 18:03

Harish_N · Answer 3 · 2014-01-30T17:32:39.667

-4

Use a non inverting amplifier with gain as 1.65.

This link could help you (http://www.instructables.com/id/Non-inverting-amplifier-with-uA741/?ALLSTEPS)

edited Jan 30 '14 at 17:32

answered Jan 30 '14 at 16:57

Harish_N

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Level shift 4 V peak to peak to 0 - 3.3 V

3 Answers3