I have calculated power as V^2 / R so 140.1 x 140.1 / 200. It was marked incorrect. I can't see what I'm missing here?
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"Power" output isn't DC values? – Antonio51 Aug 21 '22 at 12:20
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Where is this question from? I'd like to know of it's from a marked test you're currently taking or not. – Daniel Tork Aug 21 '22 at 12:23
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You're missing the angle. There's an integral as a function of $\alpha$. – a concerned citizen Aug 21 '22 at 13:14
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To be sure that it is half ..., what is your schematic. – Antonio51 Aug 21 '22 at 13:18
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Here is the behavior in two configurations of controlled rectifiers.
Half-wave ... and full-wave. EE&O.
"I" have also calculated various quantities. What is valid?
Remember and write ... the power "definition", if more than one ...
Antonio51
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