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I've designed a constant current source using a current mirror, we need an output of about 50mA. The problem is that we build it and heat has become a problem.The transistors and the R_load are both heating up which decreases beta stabilization (our amperage through our load resistor increases constantly). Original current source design I think that by adding an emitter resistor we should be able to beta stabilize but I'm not sure if I'm doing it right. Current source design with emitter resistor

wawiti
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3 Answers3

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There are a few other constant current type regulators to consider: -

enter image description here

  1. This biases a transistor to have a certain voltage across the emitter resistor and this means the current in the collector to the load is pre-defined.
  2. Can be used with a LED as load - it works by the BJT cutting the voltage supply to the gate of the MOSFET when the current thru R2 reaches "the constant current level".
  3. Classic voltage regulator turned constant current source
  4. My favourite - an op-amp used with a BJT sets (very accurately) the voltage across the emitter resistor and hence the current in the collector is very well controlled too.
  5. Pretty much the same as (4)
  6. Like (2) but with the load at the top
  7. Like (4) and (5) but with the load at the top

Also to consider are Wilson current mirrors (a definite improvement over your standard current mirror) and the Howland (and improved H) constant current source.

I don't really understand what you are trying to achieve so I can't recommend one over the other. AD have a good paper on current sources too.

Andy aka
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Given the very large head-room you have available from your primary supply, you should be able to just use the 7805 in current regulator mode:

schematic

simulate this circuit – Schematic created using CircuitLab

This would accomodate a wider range of load resistors if you could swap the 7805 out for a chip with a lower reference voltage and lower drop-out voltage.

The Photon
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Linear regulators actually make for good constant current sources because of fairly high accuracy between the output voltage and ground.

All you need is a resistor between output and ground to limit your current.

$$I_{out} = \frac{V_{out}}{R_{out}}$$

I will refer you to this Maxim application note for a more thorough explanation.

Ricardo
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Skateboarder
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