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Hamiltonian quantum computing with superconducting qubits says

The appeal of a Hamiltonian approach to quantum computing is that it does not require active driving fields to enact logic. Information carriers move through gates in space, rather than time-dependent gates being applied to stationary qubits. This means that a realization of this approach is much closer to the idea of analog quantum simulation, but with the benefit of enabling universal computation.

This implies that, unlike other models of quantum computation—such as gate-based, measurement-based, and adiabatic models—Hamiltonian quantum computing is completely autonomous. No external controls are applied to the system during computation. The operating procedure for this computer is: Initialize state, wait, and then measure the output.

Is a linear optical quantum computer also autonomous? Like a Hamiltonian quantum computer it also doesn't require active driving fields to enact logic and information carriers (photons) are moved through gates (e.g., beam splitters, phase shifters, etc.) instead of being applied to stationary qubits.

Victory Omole
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As @Jahan Claes said in the comments, a universal linear optical quantum computer is not autonomous but a Boson Sampler is. Even a non-cluster LOQC requires gate teleportation to perform multi-qubit gates. The implementation of gate teleportation requires feedforward measurements, which breaks the "Initialize, wait, measure" procedure of an autonomous computer. This places universal LOQC in the category of MBQC, not Hamiltonian QC.

Victory Omole
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