Python currently doesn't support an operator for Kronecker products. Note how the @ symbol works: when you write the statement A @ B, Python$^1$ checks the objects A and B for a __matmul__ method and then returns A.__matmul__(B). But there's no built-in operator that corresponds to something like a __kron__ method.
If you really want this functionality, one way might be to change how the * operator works by redefining __mul__ (e.g. see here or here) to perform a kronecker product, so that calling A * B would return np.kron(A, B). However this could end up being very confusing for yourself and others reading your code.
$^1$ as of Python 3.5, see PEP 465: https://www.python.org/dev/peps/pep-0465/