3

Why does applying the following circuit on a $00$ state produce $|0\rangle \otimes |+\rangle = \frac{1}{\sqrt{2}}(|00\rangle + |01\rangle)$. Shouldn't it produce $ |+\rangle \otimes |0\rangle = \frac{1}{\sqrt{2}}(|00\rangle + |10\rangle)$?

enter image description here

luciano
  • 6,084
  • 1
  • 13
  • 34
Yash Wath
  • 33
  • 3

1 Answers1

4

Qubit ordering in Qiskit: qubit 0 is the rightmost one, i.e., the least significant bit.

Yael Ben-Haim
  • 879
  • 4
  • 4