How can I find the amount of point force at the end of a cantilever plastic beam that produces e.g. 45° slope at the end of the beam? Is this the right equation: $$F=\frac{2EI\theta ^2}{L^2 \sin(\theta)}$$
I derived this equation by putting $x=\frac{L}{\theta}\sin(\theta)$ and $\theta_x=\theta$ in the following equation from the "Large and small deflections of a cantilever beam" paper: $$x=\sqrt{ \frac{2EI}{F} } \left(\sqrt{\sin(\theta)}-\sqrt{\sin(\theta)-\sin(\theta_x)}\right)$$
where $\theta$ is the maximum slope at beam end and $\theta_x$ is the beam slope at x.
