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Imagine there is a glass container with a low water level (so that sunlight doesn't lose too much energy when it gets to the bottom of the container).

Suppose the water is distilled (pure $H_{2}O$). It doesn't conduct electricity. Still, let's dip wires in water at two ends of the container and connect them to a battery.

Now let's dip a metal plate in water and keep the container in sunlight. The metal has very low ionisation energy but doesn't explode when it comes in contact with water.

As light strikes the metal surface, according to the photoelectric effect, electrons should be ejected. When electrons are ejected, those free electrons should be influenced by the electric field of the battery and so (perhaps) won't come back to the metal immediately.

So, now the water has some free electrons. Is it a conductor now?

cconsta1
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Vikram
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2 Answers2

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When electrons (photoelectrons in this case) are introduced in water , they become solvated. Such electrons are known as Solvated electrons or wet electrons.

According to the definition taken from Wikipedia,

A solvated electron is a free electron in a solution, in which it behaves like an anion . --------------(i)

Its denoted by '$e^{-}$'

also ,

An electron's being solvated in a solution means it is bound by the solution. -------------------------(ii)

So , Yes , solvated electrons in water do conduct electricity. When electrons are solvated (or hydrated) in water, they become surrounded by water molecules and are able to move within the solution, allowing for the flow of charge, which is electricity.


EDIT

After further research and with the help of the upstanding and obliging comments made by @MichaelSiefert , @JohnDoty , @cmaster - reinstate monica and others , I have come to understand that my answer is not entirely accurate and correct. I will discuss the problem and my edits in points.

  1. Reactivity of the solvated electrons - The statements (i) and (ii) mentioned above , though correct , only partially apply to the solution of this problem . The theory/statement previously suggested/stated by me , i.e. ,

So , Yes , solvated electrons in water do conduct electricity. When electrons are solvated (or hydrated) in water, they become surrounded by water molecules and are able to move within the solution, allowing for the flow of charge, which is electricity.

is only particularly correct when the pH of the solution is less than 9.6 .

Below pH = 9.6 the hydrated electron reacts with the hydronium ion giving atomic hydrogen, which in turn can react with the hydrated electron giving hydroxide ion and usual molecular hydrogen H2. -----------(iii)

So this aspect depends upon the concentration of the alkali metal sheet in the solution. If the pH is above 9.6 , then the theory/statement answered previously prevails and the solution will conduct electricity.

  1. Even if the pH of the solutions falls below 9.6 , The solution will still conduct electricity , although not by the solvated electrons but through them. I have stated the reactions along with their statements and the equilibrium constants.

In certain photochemical electron-transfer processes, in which the reducing species was formerly identified, but mistakenly, as a hydrogen atom, the characteristic absorption spectrum of $e_{aq}^{-}$ has now been observed (2). A hydrated electron is barely distinguishable chemically from a hydrogen atom, its conjugate acid, but is converted to it by reaction [1] only very slowly, if at all (3).

[1] $ e_{aq}^- + H_2SO_4 -> H + OH^- ; k_1 < 16 mole^{-1} s^{-1}$

[6] ${e_{aq}^{-} + e_{aq}^{-} -> H_2 + 2OH^-} ; 2k_6 = 4.5 \times{10^8} mole^{-1} s^{-1}$

[7] $H + H -> H_2 ; 2k_7 = 6 \times{ 10^8} mole^{-1} s^{-1}$

----------------------(iv)

Thus , the solution will conduct electricity due to the presence of $M^{+}$ (where M stands for the alkali metal) and $OH^-$ ions formed , and the solvated electron acts as an intermediate.


Here I have mentioned the Reference numbers and direct lins for the statements (i),(ii),(iii) and (iv) , along with the research papers associated with them for their references.

Wikipedia link - https://en.wikipedia.org/wiki/Solvated_electron

Research papers for statement (i) - Dye, J. L. (2003). "Electrons as Anions". Science. 301 (5633): 607–608. doi:10.1126/science.1088103. PMID 12893933. S2CID 93768664.

Direct link(s) - https://www.science.org/doi/10.1126/science.1088103 , https://pubmed.ncbi.nlm.nih.gov/12893933/ , and/or https://www.semanticscholar.org/paper/Electrons-as-Anions-Dye/7a805f3a12143fd05f95b565ed814c36849196ed

Research papers for statement (ii) - Schindewolf, U. (1968). "Formation and Properties of Solvated Electrons". Angewandte Chemie International Edition in English. 7 (3): 190–203. doi:10.1002/anie.196801901.

Direct link - https://onlinelibrary.wiley.com/doi/10.1002/anie.196801901

Research papers for statement (iii) - Jortner, Joshua; Noyes, Richard M. (1966). "Some Thermodynamic Properties of the Hydrated Electron". The Journal of Physical Chemistry. 70 (3): 770–774. doi:10.1021/j100875a026.

Direct link - https://pubs.acs.org/doi/abs/10.1021/j100875a026

Research papers for statement (iv) - Walker, D.C. (1966). "Production of hydrated electron". Canadian Journal of Chemistry. 44 (18): 2226–. doi:10.1139/v66-336.

Direct link(s) - https://cdnsciencepub.com/doi/pdf/10.1139/v66-336 , https://cdnsciencepub.com/doi/10.1139/v66-336

These research paper links can be found under the 'References' section of the given Wikipedia page.


NOTE - I tried to to apply the \ce command for the chemical equations, but it is not working , and I don't know why. Please help me edit the forward reaction arrow , if not the equations in statement (iv). Thank You .

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Only in the region extremely close to the metal. To begin, consider the situation with just the metal in water under light: electrons are liberated from the metal with a certain energy spectrum determined by the spectrum of incident light and the metal's work function. After these electrons are liberated, the metal has a net positive charge, and electrons are attracted back to the metal. An equilibrium is then reached between electrons leaving the metal and being drawn back to it. This is not really different to a sheet of metal electrically isolated in vacuum being irradiated. To put it in a schematic (yellow arrow represents light, black rectangle is the metal, circled negative signs are solvated electrons, plus signs are net positive charges left by ejected electrons):

Photoelectric effect steady state schematic

However, the lifetimes and mean free paths of solvated electrons in water are both extremely short (fractions of a nanosecond and nanometres), so this only affects the region of water extremely close to the metal. The bulk of the water effectively does not know that this is happening. If an electric field is applied through the water by a battery it will almost instantaneously distort this steady-state electron distribution very slightly, pushing the electrons closer to the positive terminal, but the conductivity of the water will not change from the very low value provided by $\text{H}_3\text{O}^+$ and $\text{OH}^-$ ions from self-ionisation.

llama
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