TLDR: if two unbounded objects are accelerated simultaneously, the ill-named length contraction states that in the proper frame, they move away from each other. But what about in real life where there is no such thing as unbounded objects: does a bus elongate in its proper frame after its acceleration to reach the highway?
Preliminaries:
A system $\Sigma$ consists of two initially unconnected subsystems, A and B.
- State 1: A and B are stationary in the reference frame $R_0$ and are separated by a distance $L_0$.
- State 2: A and B are set in motion simultaneously and identically in $R_0$, reaching the same constant velocity $v$ along their initial separation axis (AB). This state is defined such that A and B have been moving at this velocity for a time much longer than their acceleration phase (to avoid any debate about this stage).
Since A and B accelerated simultaneously in $R_0$, they remain at the same distance $L_0$ from each other in this frame. Thus, due to length contraction (or the relativity of simultaneity, whichever you prefer to invoke), in the proper frame of $\Sigma$, denoted $R_p$, the distance between A and B, $L_p$, is greater than $L_0$. This means that in $R_p$, A and B must have moved apart such that their separation increased from $L_0$ to $L_p$.
Actual Question:
Now, let's consider a similar situation, but this time A and B are connected or bounded to each other. As an example, take a spring, though the specific connecting mechanism does not matter.
- In State 1, where the distance between A and B is $L_0$, the spring exerts no force, A and B do not move relative to each other, and the natural length of the spring is $L_0$.
- We consider a case with dissipation, meaning that if A and B move relative to each other, they do not oscillate but instead reach an equilibrium position after damping effects.
The question is: What is the distance between A and B in each reference frame, $R_0$ and $R_p$, once $\Sigma$ has reached its cruising velocity $v$?