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Circuit Diagram

figure of the question



How are we supposed to find the resistance
What I tried:

The middle one remains isolated
However, the upper ones and lower ones add up
So, there are 2 resistors of 2ohms and one resistor of 1ohm, all three in parallel

Hence, R(equivalent) would be:

$$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} $$ $$ \frac{1}{R} = \frac{1}{1} + \frac{1}{2} + \frac{1}{2} $$

This gives R(equivalent) as a $\frac{1}{2}$, which is not correct
So, how am I supposed to do it.

Qmechanic
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2 Answers2

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This is one of those horrible textbook questions designed to confuse students.

The middle-most resistor is supposed to be rotated. Then you can straighten and align all the other resistors so show a very symmetric version of it. Then you will realise that it is basically very easy to solve. But it requires that you first be able to redraw this circuit to be in that symmetric and obviously simple form, or else you cannot hope to see why the answer is simple.

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