As 1 coulomb electrons go through 1 volt of potential difference, they gain 1 joule of energy. So in s series circuit, do electrons move faster towards the end of the circuit where they went though a larger potential difference? If so, how is the current through a series circuit constant?
Asked
Active
Viewed 47 times
1 Answers
1
If that circuit is an accelerator beam pipe, then: yes, that's the point.
If it's something with plain old resistance, then they loose $IV\tau = 1\,{\rm J}$ of energy to resistive heating, where tau is the unspecified time over which this 1 C drops 1 V.
JEB
- 42,131