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I am little confused.Please correct me if I am wrong. According to general relativity, there is no way to spot a difference between accelerating frame of reference and gravity.

Suppose a spacecraft is accelerated in space then we can not distinguish between the accelerating frame of reference and gravity.

My question is: How fast the acceleration should be that the spacecraft acts like a black hole? (Black holes have been observed therefore I am assuming such an acceleration should be possible.)

John Rennie
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2 Answers2

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There is an (apparent) event horizon in any accelerating frame: that is, if you are accelerating and keep accelerating then light from some distant events behind you will never reach you. The distance from the spaceship to this horizon is $c^2/a$, where $a$ is the proper acceleration of the spaceship; see Wikipedia for details (look under "apparent horizon of an accelerated particle"). Of course this horizon only persists as long as the spaceship keeps accelerating, which in practice isn't very long compared to the distances involved, so we never notice it in everyday life.

Note that this apparent horizon differs quite substantially from the event horizon of a black hole, in that it is only a horizon for the observer in the spaceship. This is to be expected. The equivalence principle has a lot of caveats that are very important in practice: a uniformly accelerating reference frame is equivalent to a uniform gravitational field in a small enough region of spacetime. Acceleration is thus not "the same" as gravity, but it acts "like" gravity if you only consider a small enough region of space and small period of time. Real gravitational fields (such as produced by a black hole) are very far indeed from being uniform.

Eric Smith
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I think what you are thinking about is the Unruh effect. As far as the answer to your question is concerned, at any acceleration the observer would observe Unruh radiation which will be indistinguishable from Hawking radiation. However, if you want Unruh radiation to be highly significant the acceleration needs to be many order of magnitude high.