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Why does Quantum Field Theory use usually Lagrangians rather than Hamiltonains?

I heard many reasons, but I'm not sure which is true.

Some say it's just a matter of beauty, so Lagrangians are more beautiful because they don't break/separate the space-time variables (so space-time is a single variable, like in the Klein-Gordon Lagrangian and Hamiltonian).

Some say that Hamiltonians are not always Lorentz invariant.

Could someone explain in a little bit more details?

Qmechanic
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1 Answers1

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You have already mentioned the correct reason---the Lagrangian is manifestly Lorentz-invariant whereas the Hamiltonian is not. Since a relativistic field theory must be build of Lorentz-invariant quantities only the Lagrangian approach is good.

Compare for example the expressions for a free real scalar field $\phi$ $$ \mathcal{L}=\frac{1}{2}\partial_\mu\phi\partial^\mu\phi $$ This is Lorentz-invariant, because the Lorentz index $\mu$ is contracted in this way. The Hamiltonian for this theory is $$ H=\frac{1}{2}\dot\phi^2+\frac{1}{2}(\vec\nabla\phi)^2 $$ which is not manifestly Lorentz-invariant.

Is there any other reason?

Stan
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