1

In Greiner's Classical Mechanics, vol. 2 (Springer 2010, p. 59), he mentions that differential cross-section in Rutherford scattering diverges as scattering angle goes to 0, i.e. when impact parameter goes to zero. Then he writes: "This is due to long-range nature of the Coulomb force. If one uses potentials which decrease faster than 1/r, this singularity disappears." I figure this singularity is the reason why the total cross-section in Rutherford scattering in Coulomb field is infinite. So, if, according to this text, the singularity is weakened by other type of potential (e.g. Yukawa), then the total cross-section might become finite?

I do not understand, however, how it can be finite. As long as the potential only goes asymptotically to zero (and never becomes zero), the total cross-section should be infinite (since the particle will feel the effect of the target at any distance and will be deflected), even if the potential decays very fast with r.

user373714
  • 23
  • 7

0 Answers0