The MPP is the maximum power point of a solar panel and a PV inverter will typically try to find this MPP to yield the maximum energy ouput. But sometimes it might be neccessary to operate the panel away from the MPP to reduce power output (because the grid operator needs to reduce feed-in or because the inverter can't handle that much power, or whatever). Starting from the MPP, the inverter can go two ways to reduce power:
- It can increase the current drawn from the panel to force a lower voltage output from the panel
- It can decrease the current drawn from the panel. Power will go down, because the voltage will not increase by the same factor. I assume this is the preferred implementation to reduce wear of the inverter.
So the power the inverter can feed to the grid reduces in both cases, but the solar irradition to the panel is not changing. Where is the excess energy going?
In case 1) it feels quite intuitive to say the higher current results in higher conduction losses in the panel and increases panel temperature. Is that correct?
In case 2) I'm a little lost. When we draw less current than the panel is capable of delivering with a given solar irradiation we probably have some surplus free charge carriers? Are they somehow reducing efficiency of the panel, so that less photons are converted to electric energy but just directly heat up the panel?
PS: There is already this question, but there is not really a good answer for my question.