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This is probably a very basic question about notation. If we have the following notation for Boron nuclei:

$$^{12}_5 B(1^+)\;\text{or}\; ^{10}_3B(3^+)$$

What does the number in the parentheses mean? I guess $1$ and $3$ correspond to a spin number and $\pm$ to the parity. But what spin is that exactly and how do you find it?

Qmechanic
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1 Answers1

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I think the nuclear spin or the total angular momentum. See Possible spins and parities of $^{38}_{17}Cl$

MrQ
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