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Perhaps a bit of a strange question. I know the traditional way of finding a black hole's surface area is through the Schwarzschild radius,

$$ r_{\rm{Schwarzschild}}=\frac{2GM}{c^2} $$

however, that equation is formed from the assumption that there is no preference on direction; so it seems odd to do something like M'=gamma M or a length contraction, even when assuming that the observer is far enough away that space-time could be considered flat.

Any help on this would be greatly appreciated!

Qmechanic
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Nathan Stone
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1 Answers1

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Let's say we have a big box. The volume and the surface area of the box is the largest in its rest frame.

Let's say there is a small black hole inside said box.

The black hole shines Hawking radiation equally to all faces of the box. This is an invariant.

Now we can see that the black hole must Lorentz-transform the same way as the box. Right?

stuffu
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