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enter image description here In this part has this identity and I could not understand, why factor 4, for me

$$k^{\mu}k^{\nu}=g^{\mu\nu}k²$$

Since $$k²=k_{\mu}k^{\mu}.$$

Unless the notation is the same but the product is different,Could someone explain to me why(the context is anomalous magnetic moment of electron)

Reference: M.D. Schwartz, Quantum Field Theory and the Standard Model; page 338.

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1 Answers1

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Schwartz is using the fact that under the integration sign $$\int_{\mathbb{R}^d}\! \frac{d^dk}{(2\pi)^d} f(k^2) k^{\mu}k^{\nu} ~=~\int_{\mathbb{R}^d}\! \frac{d^dk}{(2\pi)^d} f(k^2) k^2 g^{\mu\nu}/d,$$ where $d$ is the spacetime dimension, cf. e.g. Ref. 2, this related Phys.SE post, and above comment by Oбжорoв.

References:

  1. M.D. Schwartz, QFT & the standard model, 2014; section 17.2.

  2. M.E. Peskin & D.V. Schroeder, An Intro to QFT; eq. (6.46).

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