What does the line integral of $\int\vec{s}\cdot d\vec{F}$ represent, where $s$ is the total displacement, and $dF$ is the force differential?

Question

I recently started reading Feynman Lectures on Physics (Vol 1). I came across the formula for work done as,

Work done is $\int\vec{F}\cdot d\vec{s}$

My question is:

What does $\int\vec{s}\cdot d\vec{F}$ represent?

Does it even make sense to calculate the product of total displacement and small amount of force?

or does $\int\vec{F}\cdot d\vec{s}$ have the same meaning as $\int\vec{s}\cdot d\vec{F}$, they both represent the work done?