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I'm trying to derive the thermodynamics of the black hole solution presented at A New Class of Exact Hairy Black Hole Solutions by Kolyvaris et al.

I'm asking for resource recommendations on this matter, $3+1$ decomposition, boundary terms etc. Is there any paper that derives black hole thermodynamics, using the Euclidean method, for a simpler solution and describes the procedure in detail?

An answer presenting the calculation and procedure in detail is also appreciated!

Noone
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1 Answers1

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As a fundamental tool in black hole thermodynamics, the Euclidean method has been applied to both complicated and simple solutions. The sources I would read are the following.

  1. Thermodynamics of black holes in anti-de Sitter space by Hawking and Page. This is the paper which first developed the method and it is very readable. The calculation starts in section 2 and one cannot help but notice how streamlined it is compared to Hawking's earlier tour de force which derived evaporation for black holes in Minkowski space.
  2. Anti de-Sitter space, thermal phase transition and confinement in gauge theories by Witten. This starts off by reviewing the Hawking Page calculation for AdS black holes and generalizing it to $n$ dimensions. Later on, we get to see it applied in a situation which still receives much attention, obtained by compactiying AdS on a circle in order to give the dual gauge theory a scale.
  3. Previous SE answers from 2013 and 2017.

As discussed in the latter, a major point of the derivation should already be familiar if we think about converting between polar and Cartesian co-ordinates for Euclidean space. \begin{equation} ds^2 = dr^2 + r^2 d\theta^2 \to ds^2 = dx^2 + dy^2 \end{equation} The polar form shows a vanishing component at $r = 0$. This is shown to be merely a co-ordinate singularity IF we can write it in the Cartesian form. However, writing it in the Cartesian form is only valid if $\theta$ is $2\pi$ periodic because we need to be able to set \begin{equation} (x, y) = (r\cos \theta, r\sin \theta). \end{equation} In other words, \begin{equation} ds^2 = dr^2 + r^2 d\theta^2, \;\;\; \theta \in [0, \alpha] \end{equation} is a different manifold from Euclidean space when $\alpha \neq 2\pi$. It is situations like these which show us that the Einstein Hilbert action is a functional which acts on manifolds. Writing it as something which acts on the metric alone is abuse of notation. This is similar to how tori $\mathbb{T}^2$ with different complex structures $z \sim z + 2\pi \tau$ are also different manifolds. Because even though tilting the axes is innocuous in $\mathbb{R}^2$, it becomes meaningful when there are periodicities involved.

Let's see how this works for the Euclidean Schwarzschild metric \begin{equation} ds^2 = \left ( 1 - \frac{2M}{r} \right )d\tau^2 + \left ( 1 - \frac{2M}{r} \right )^{-1} dr^2 \end{equation} by forcing it to pick up a simple $d\rho^2$ term in a new co-ordinate system. This means we need to solve \begin{equation} dr = \sqrt{1 - \frac{2M}{r}} d\rho \end{equation} which is separable. The solution is \begin{equation} \rho = \mathrm{const} + \sqrt{8M(r - 2M)} + O(r - 2M). \end{equation} We can now plug this into the metric and again drop higher powers of $r - 2M$ to find \begin{equation} ds^2 = d\rho^2 + (\rho / 4M)^2 d\tau^2 \end{equation} near the horizon. Then in precise analogy with the polar co-ordinate example above, $\tau / 4M$ needs to have period $2\pi$. This implies that the inverse temperature (the period for $\tau$ itself) is given by \begin{equation} \beta = 8\pi M \end{equation} which is the well known result.

Connor Behan
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