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I am trying to do this functional integral:

$$F_{2D}[\alpha,\phi] = \int\limits_{ \Phi(\cos(\theta),\sin(\theta))=\phi(\theta)} \exp \left( i\alpha\int\limits_{x^2+y^2<1}\Phi(x,y)(\partial_x ^2 + \partial_y ^2)\Phi(x,y) dx dy \right) D\Phi$$

In other words it is a functional integral where the boundary is a circle which and the field has values $\phi(\theta)$ on the boundary. Inside the circle the fields can take on any values.

I would imagine this would correpond to some kind of "quantum drum". The answer would depend only on the constant $\alpha$ and the height of the drum on the boundary $\phi(\theta)$. I feel like this should be solvable interms of elementary(ish) functions.

This is a generalisation of the simpler example of a the 1D case:

$$F_{1D}[\alpha,A,B] = \int\limits_{\Phi(0)=A}^{\Phi(1)=B} \exp \left( i\alpha\int\limits_{0}^{1}\Phi(x)\partial_x ^2 \Phi(x) dx \right) D\Phi = \sqrt{\alpha/2\pi i}\exp(-\alpha(A-B)^2/2i)$$

But I can't find if the 2D case this been solved anywhere or even how to begin? If not a circular drum, maybe a square drum would be easier?

Actually I do have one idea and that is to expand the fields $\Phi(x,y)=\sum a_{nm}(\phi) H_{nm}(x,y)$ into a set of orthogonal functions that satisfy the boundary conditions. But that is as far as I got. In other words it would be summing over all vibration modes of a circular membrane.

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After a lot of investigating I think the answer is likely to be:

$$F_{2D}[\phi] \propto \exp\left(i \int\limits_0^{2\pi}\int\limits_0^{2\pi} \frac{\phi(\theta)\phi(\theta')}{1-\cos(\theta-\theta')} d\theta d\theta \right)$$

but I can't prove it yet. If not this then something very similar with $\cos$ replaced with a similar function.