The energy stored in a charged capacitor of capacitance $C$ with $V$ voltage across it is:
$$U= \frac 12 CV^2$$
Whereas the work done in charging the capacitor is:
$$W= CV^2$$
This means that $(1/2)CV^2$ amount of energy gets dissipated somewhere else.
I learnt somewhere that this is dissipated as heat. But an ideal circuit having just a capacitor with a battery (without internal resistance) provides no resistance.
So:
- How and where does half of the work done in charging a capacitor gets dissipated?
