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I know Hamiltonian can be energy and be a constant of motion if and only if:

  1. Lagrangian be time-independent,
  2. potential be independent of velocity,
  3. coordinate be time independent.

Otherwise $$H\neq E\neq {\rm const},$$ or $$H=E\neq {\rm const},$$ or $$H\neq E={\rm const}.$$

I am looking for examples of these three situation.

Qmechanic
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1 Answers1

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Example. Time-dependent gravitational acceleration ($H=E$ but $\dot E \neq 0$)

Consider a particle falling under the influence of gravity near the surface of a large, spherically symmetric planet. Suppose that the mass of the planet changes with time, so that the acceleration due to gravity near the surface is some function $g(t)$ of time. Then the Lagrangian is $$ L(t, z, \dot z) = \frac{1}{2}m\dot z^2 - mg(t)z $$ then the canonical momentum conjugate to $z$ is $$ p_z = \frac{\partial L}{\partial\dot z} = m\dot z $$ and the Hamiltonian is $$ H = p_z\dot z - L = \frac{p_z^2}{2m} +mg z $$ Notice that in this case $H(t) = E(t)$; the Hamiltonian is equal to the total energy. Now, in this case, the equations of motion are $$ \dot p_z(t) = -mg(t) $$ So for any solution $z(t)$ to the equations of motion, we have $$ \dot E(t) = p_z\dot p_z + m(\dot gz + g\dot z) = p_z(\dot p_z + mg) + m\dot g z = m\dot g z\neq 0 $$ Total energy is not conserved, it changes as a function of time due to the fact that the gravitational acceleration depends on time.

joshphysics
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