3

In this paper "Photonic Floquet Topological Insulators" the authors calculate the bandstructure of a time-periodic Hamiltonian. They create a time-dependent tight-binding Hamiltonian via the Peierl's substitution.

Now my first question would be about equation (3) of this paper. Since it is in lattice site basis, would i need to FT in order to get to transverse crystal momentum basis so i can create a bandstructure? And what would happen to the phase factor aquired through the Peierls substitution?

Secondly, how would I calculate the Floquet quasi-energies from there? From what I have read so far they are usually calculated by calculating the Eigenvalues of the stroboscopic time-evolution operator $U(T)=\mathrm{exp}\left[\int_{0}^{T}{H(t)dt}\right]$. This has not worked for me so far. Is this even the right approach?

I hope this question is not too "do-my-homework-for-me"-y. Its a completely new topic for me and I have been trying to solve this for what feels like and eternity. Any help would be greatly appreciated.

1 Answers1

2

In that paper, the authors are looking at a honeycomb lattice, which is well-known as the lattice of graphene. This is not a simple Bravais lattice, but has a two atom basis which gives rise to the two bands. There is a lot of literature treating how to obtain the bandstructure for this sort of lattice, which as you say, corresponds to making a Fourier transform to to momentum space, so I would like to concentrate on the second part of your question, how to obtain the quasienergy spectrum.

You are correct to say that the quasienergies can be obtained from the time-evolution operator for a single period, $U(T)$. As $U$ is unitary, its eigenvalues are pure phases, which are related to the quasienergies $\epsilon_j$ via $\lambda_j = \exp[-i T \epsilon_j ]$. So a typical procedure is to prepare $U(T)$ by time-evolving the identity matrix over a single period of driving, finding its eigenvalues, and then taking their logarithm (and dividing by a factor of $T$).

Clara Díaz Sanchez
  • 2,415
  • 1
  • 10
  • 21