When a photon is emitted from a far away source and then measured by an observer, there is a loss of energy or redshift which takes place. Why does this happen?
I have read this similar post, however the confusion I'm having is due to the invariance of photons, which travel at the speed of light, to non-inertial reference frames. If they are invariant then why would there be a perceived energy loss as it switches from one reference frame to the other?
Suppose A emits light to Earth at some position X (That is, the rocket is located at position X). If A is stationary with respect to Earth, then if A emits 1 pulse per minute, position X receives 1 pulse per minute (because the rocket is at X), and Earth will receive 1 pulse per minute.
Now A begins to move away from X. At t = 0, A emits a pulse at position X, but at t=1minute, A emits another pulse as before, but this time A's position is X + h (assuming moving at v= h). Now as this pulse travels towards Earth, it doesn't reach position X until time h/c, where c = speed of light.
So while previously the frequency of light at position X was 1 pulse per minute. The gap between the pulses is now (1 + h/c) minutes.
Similarly, as the pulses reach Earth, they will be separated by (1+h/c) minutes. Thus the frequency of the pulses has appeared to decrease (Doppler broadening).
We can see from above, that this broadening is due to light from each consecutive pulse having to travel a greater distance than the previous pulse when the rocket is moving, thus creating a time delay.
You need to careful about treating photons as particles like electrons. A photon is best thought of the unit of interaction of the photon field. The light from distant galaxies isn't like a hail of little bullets coming towards us. The photons are delocalised and don't have a particle like position until they interect with your eye/CCD/whatever.
Anyhow, the reason light from distant galaxies is red shifted is that the spacetime in between us and the distant galaxy has expanded since the light was emitted, and that means the energy of the light has been spread out over a larger area.
One has to note energy is not "invariant" with lorentz transform. Simply put, if you are at rest, you find yourself with 0 kinetic energy; if an observer B is moving with velocity v against you, he is to find you with kinetic energy $$ 1/2mv^2$$. Energy is naturally different in different frames.
Energy and momentum make up a four vector that transforms with space-time transformation, it is called a energy-momentum vector.
