I'm trying to prove that the Wilson loop operator is well-defined in non-interacting quantum electrodynamics without matter, that is, $\hat{W}(\gamma)$ is a bounded operator on the Hilbert space.
Since the Wilson loop is an exponentiation $$ W(\gamma) = \exp \intop_{\gamma} A_{\mu} dx^{\mu}, $$
and an exponential of a bounded operator is bounded, if I can prove that
$$ \intop_{\gamma} A_{\mu} dx^{\mu} $$
is bounded then I'm done.
However, I don't see how to show that.
In a typical Wightman QFT, quantum fields are linear functions from test functions on space-time to bounded operators on the Hilbert space. So for all rapidly decaying $f^{\mu}(x)$,
$$ \int d^4 x A_{\mu}(x) f^{\mu}(x) $$
is a bounded operator on the Hilbert space. There certainly exist deformations $f^{\mu}(x, \varepsilon)$ that approach a loop $\gamma$ in the $\varepsilon \rightarrow 0$ limit, so maybe the Wilson loop operator can be defined as the limit of $$\hat{W}(\gamma) = \exp \lim_{\epsilon \rightarrow 0} \hat{A}(f^{\mu}(x, \varepsilon)), $$
however, a limit of bounded operators is not necessarily bounded.
How can I prove that the Wilson loop operator is bounded?