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Beams A and B are of different colors.

I am trying to understand how both the lights would impact each others' wavelength.

So Color IS EQUIVALENT TO Wavelength

What will be the color of the areas labelled C,D and E?

 \   \          /   /
  \   \        /   /
   \   \      /   /
    \ A \    / B /
     \   \  /   /
      \   \/   /
       \  /\  /
        \/C \/
        /\  /\
       /  \/  \
      /   /\   \
     / D /  \ E \

What will be the final color of C,D and E?

Will C be a mixture of A and B? If yes, then how.

Will D and E have the color B and A respectively?

Answers with citation or proof of practical demonstrations shall be given more preference over those which do not have them.

Nephew of Stackoverflow
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1 Answers1

2

What will be the final color of C,D and E?

"Color" is something that only happens in your brain. Photons have energy/wavelength.

The photons that pass by E are the same photons that earlier passed by A. They are completely unaffected by the crossing of the beams. Likewise, the photons that pass by D are the same photons that earlier passed by B, and they too are unaffected.

If you place a white card at any one of those places, photons will reflect off of it in all directions. Some of them will enter your eyes, and you will see a bright, colored spot on the card.

Photons reflected form a card at A, or E will cause you to see one color, and photons reflected from a card at B or D will cause you to see a different color.

At location C, the card will reflect photons of both wavelengths. The photons still are unaffected by each other, but when photons of the two different wavelengths come from the same location (the spot on the card) and enter your eyes together, your brain will perceive a third color, different from the other two.

Solomon Slow
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