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Let there be two children Allen and George .

now Alan boards a train and the train moves at a speed comparable to light. now because George is on the station for George being at rest Allen is moving and its lock is moving slowly so time passes slower for Allen and faster for George. for George after sometime when he will be very old then Allen will be of lesser age.

now but Allen in his own frame in train sees George moving in the opposite direction.so for him George is moving and so the clock of George must be moving slowly hence for Allen George time is running slower than his.

after sometime when he will be old enough then George will be of lesser age as he was standing on the platform but moving for Allen so my question is if George if Georges on the platform and sees that Allen old and, when Allen is in the train thinking he is at rest and observe George he will see George younger

then wont it be a contradiction that both will see each other relatively younger when both meet each other?

Also if there is a third person who is also a twin to George and Allen who is moving in another train but it is lower than alan's train and so he must see George at a different age than Allen right then please tell how will the third person and Allen willbdisagree or agree about George age?

1 Answers1

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It is true they will both observe the other twin's clock as running slower than their own. But to meet again, the twin on the train moving close to light speed, will have to decelerate, stop, and accelerate back to return. acceleration and deceleration slow time like gravity does. So while Alan is decelerating and accelerating, George will see Alan's clock slow much more, and Alan will see George's clock speed up enough so that when he returns to the station they will both see that George is older than Alan.