Accordingly to the result
$$ (\bar{\psi}\psi)^\dagger = (-1)\bar{\psi}\psi \tag1$$
coming from the fact that fields with and without bar anti-commutes, you can deduce that the QCD mass term
$$ -m\bar{\psi}\psi, \quad m \in \mathbb{R} \tag2$$
is not hermitian, so QCD Lagrangian is not. Nevertheless, it has to be hermitian since we have the scattering matrix to be unitary. What is happening here?
