In quantum theory, if the atom is in a spherically symmetric state, as typically it will be in the ground state, then nothing happens to the wavefunction when you rotate the coordinate system.
Here is an example wavefunction for an atom in such a state, in some given inertial frame, expressed in spherical polar coordinates:
$$
\psi(r,\theta,\phi) = N e^{-r/a} .
$$
As you see, there is no dependence on $\theta$ and $\phi$. Now let's see what form this wavefunction takes when we change to a reference frame rotating at one zillion revolutions per second about the centre of the atom. In the new frame the wavefunction is
$$
\psi(r,\theta',\phi') = N e^{-r/a}
$$
It's the same! Similarly, if you apply to the atom an active transformation that would induce rotation if the atom were not spherically symmetric, then all you get is
$$
\psi = N e^{-r/a} .
$$
No change.
The upshot of all this is that there is no such thing as rotation for a physical entity which is truly spherically symmetric right down to its quantum details. The state of affairs that you might want to say is 'rotating' is not in fact a different state from the one you have when it is not rotating. So there really isn't any degree of freedom there. It's not just hard to get it to rotate. It's a mathematical impossibility.
Having said that, in the case of atoms one can always disturb the electron's wavefunction into some non-spherically symmetric form, and then rotation is possible. That would typically require a collision or something that supplied to the internal motion several electron-volts of energy.