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Consider a string with both ends fixed. If somewhere in middle of it be pulled and released, how would it oscillate and what is it's equation?

My solution assuming the result is a standing wave:

The point which is pulled will be an anti-node, so the length of string before this point is $(2n-1)\times\frac{\gamma}{4}$ and the length of string after this point will be $(2n^\prime-1)\times\frac{\gamma}{4}$. Considering the first length $l$ and the second length $l^\prime$, we will have: $$\frac{2n-1}{2n^\prime-1}=\frac{l}{l^\prime}$$ So the oscillator will be in it's $n+n^\prime -1$ harmonic. But what if that equation doesn't have natural answer, and what if it has answer so double of that is still an answer?

Qmechanic
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1 Answers1

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Mathematically the shape of the string is the superposition of multiple standing waves. In general it has the form:

$$ y(x,t) = \sum_{i=1}^{\infty} \sin \left(i\frac{ \pi x}{\ell} \right) \left( A_i \sin \left( i\frac{ \pi c t}{\ell} \right)+ B_i \cos \left( i\frac{ \pi c t}{\ell} \right) \right) $$

where $\ell$ is the length from end to end, and $c$ is the speed of wave propagation along the string.

Now given an initial pluck of the string, of triangular shape you find the coefficients $A_i$ and $B_i$ using Fourier transform. The result is:

$$ \begin{align} A_i &= 0 \\ B_i &= Y \frac{2 \ell^2 \sin \left( \frac{i \pi x_p}{\ell} \right)}{\pi^2 i^2 x_p (\ell-x_p)} \end{align} $$

where $x_p$ is the position of the pluck point, $Y$ is the pluck amplitude, and $i=1 \ldots \infty$

To arrive at this use the pluck shape $y_0(x) = Y\,{\rm if}(x \leq x_p, \tfrac{x}{x_p}, 1-\tfrac{x-x_p}{\ell-x_p})$ and the known initial conditions $$ \begin{aligned} \lim \limits_{t\rightarrow 0} y(x,t) & = y_0(x) = {\rm triangle} \\ \lim \limits_{t\rightarrow 0} \frac{\partial}{\partial t} y(x,t) & = v_0(x) =0 \end{aligned}$$

Now pre-multiply with $\sin\left(i \frac{\pi x}{\ell} \right)$ and integrate over the length of the string

$$ \begin{aligned} \int \sin\left(i \frac{\pi x}{\ell} \right) y_0(x) {\rm d}x &= \int \sin\left(i \frac{\pi x}{\ell} \right) \lim_{t\rightarrow 0} y(x,t) {\rm d}x = B_i \frac{\ell}{2} \\ \int \sin\left(i \frac{\pi x}{\ell} \right) v_0(x) {\rm d}x &= \int \sin\left(i \frac{\pi x}{\ell} \right) \lim_{t\rightarrow 0} \frac{\partial}{\partial t} y(x,t) {\rm d}x = A_i \frac{i\,\pi\, c}{2} \end{aligned} $$

or

$$\begin{aligned} A_i &= \frac{2}{i\,\pi\,c} \int \sin\left(i \frac{\pi x}{\ell} \right) v_0(x) {\rm d}x = 0 \\ B_i & = \frac{2}{\ell} \int \sin\left(i \frac{\pi x}{\ell} \right) y_0(x) {\rm d}x = \frac{2 Y \ell^2}{\pi^2 i^2 x_P (\ell-x_p)} \sin\left(i \frac{\pi x_p}{\ell} \right)\end{aligned} $$

John Alexiou
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