In order for a vibration to be IR active, there must be a change in the dipole moment ($\mu$) of the molecule, which is given by:
$\mu$ = $\sum$ q * r
Where q is the charge magnitude and r is the distance between the two charges.
Now, whenever I see a classical description of Raman spectroscopy, it starts off by describing the formation of an induced dipole in a molecule due to an electromagnetic field:
$\mu$ = $\alpha$ * E
Where $\alpha$ is the polarizability and E is the magnitude of the electromagnetic field.
When the E field oscillates, it also causes the induced dipole to oscillate. Since we have an oscillating dipole, how is this not IR active?
What is the difference between the induced dipole occurring in the IR example vs the Raman example? If someone could describe this answer in terms of oscillating electron and protons, I think it might help as well.