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This question follows from a previous SE question asking how the thickness of a material affects the acoustic transmission coefficient.

This website seems to suggest that the equations defining the compliance and inertance components of specific acoustic impedance ($z$) are dependent on a certain assumption of scale:

Both use the idea of a compact region: a region whose dimensions are much smaller than the wavelengths we are considering.

Further searching suggests this simplifying approach is also sometimes called acoustical compactness:

The ‘size’ of the body at a given frequency is called its compactness and is characterized by the parameter $ka$ where $a$ is a characteristic dimension, or by the ratio of characteristic dimension to wavelength $a/λ$. A compact source, one with $ka ≪ 1$, radiates like a point source, while non-compact bodies must be treated in more detail, as we saw in the case of a sphere in §2.1.


Does this mean the usual equations describing acoustic impedance cannot be applied when a media layer has thickness $a \ll \lambda$ ? I can imagine that pressure starts to become more complicated to describe at this scale, but how exactly is the assumption involved?

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No, it does not. consider 1/4" thick lead sheeting: it does an excellent job both absorbing incident sound of certain frequencies and reflecting other frequencies. plane wave incidence of sound waves and the related equations for reflection and transmission as functions of impedance ratios work well in that regime.

niels nielsen
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