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In AC, there are $R$, $C$, & $L$ or $R$, $X_C$, & $X_L$. $$ X_C = \frac{1}{\omega C} $$ where $\omega=2\pi f$.

But sometime we're using the $X_C = \frac{1}{j\omega C}$. I understand the $j$ is the imaginary unit and it's current lead voltage in capacitance circuit. But why does the equation sometimes have $j$ and sometimes don't?

By Symmetry
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1 Answers1

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But why does the equation sometimes have j and sometimes don't?

The reactance $X$ is the imaginary part of the impedance $Z$ (which is a complex number):

$$Z = R + jX$$

and so, $X$ is a real number, i.e., there should never be an $i$ or a $j$ in the formula for a reactance.

Thus

$$X_L = \omega L,\qquad Z_L = jX_L = j\omega L$$

$$X_C = -\frac{1}{\omega C}, \qquad Z_C = jX_C = -j \frac{1}{\omega C} = \frac{1}{j\omega C}$$